SOLUTION: Q: e^(2x+5)=40 its pretty simple i think, this is what i've figured out. ln(e^(2x+5))=ln(40) 2x+5=ln(40) 2x+5 = 3.688 2x = -2.688 x = -1.344 im not sure if thats right,

Question 152520: Q: e^(2x+5)=40
its pretty simple i think, this is what i've figured out.

ln(e^(2x+5))=ln(40)
2x+5=ln(40)
2x+5 = 3.688
2x = -2.688
x = -1.344
im not sure if thats right, i didnt really pay attention in logs,and e's.
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Quickest way to check is to plug your solution into the equation and make sure it solves it.

Oops, there's a problem.
You paid attention for logarithms but not during subtraction.
Your thinking and approach to the problem are clear.

It should be,

Checking,

Close enough.
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