SOLUTION: How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents please

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents please      Log On

Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 147842: How do you solve y^(-1/3) -3y^(2/3) /y^(-4/3)? No decimals or negative exponents please
Answer by stanbon(48569) About Me  (Show Source):
You can put this solution on YOUR website!
y^(-1/3) -3y^(2/3) /y^(-4/3)
Factor the numerator to get:
= y^(-1/3)[1 - 3y]/y^(-4/3)
Simplify to get:
= y(1-3y)
Change form:
= y - 3y^2
==============
Cheers,
Stan H.