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put this solution on YOUR website!-2 log base3 (1/x) + 1/3 log base3 square rt(x)
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rewrite using exponents, the reciprocal gets rid of the negative:
:
logb3(x^2) + (1/3)*logb3(x^(1/2)); note that the

= x^(1/2)
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logb3(x^2) + logb3(x^(1/6)); multiply the exponents 1/3*1/2
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Plus means multiply, add exponents: (2 + 1/6 = 12/6 + 1/6)
:
logb3(x^2*x^1/6)) = logb3(x^(13/6))