SOLUTION: Solve with exact solutions
log2(x)-log2(3x-1)=0
I only got this far
logbase2(x/3x-1)
Algebra.Com
Question 139563This question is from textbook College Algebra
: Solve with exact solutions
log2(x)-log2(3x-1)=0
I only got this far
logbase2(x/3x-1)
This question is from textbook College Algebra
Answer by oscargut(2103) (Show Source): You can put this solution on YOUR website!
log2(x)-log2(3x-1)=0
then
log2(x/3x-1)=0
then
x/(3x-1)=1 (because 2^0=1)
then
x=3x-1
-2x=-1
x=1/2
RELATED QUESTIONS
#1. Log2(3x-7)+log2(x+2)=log2(x+1)
#2.... (answered by CPhill,ikleyn)
solve for x
log2 x + log2... (answered by jsmallt9)
Solve log2(x+2) =... (answered by stanbon)
solve for x:... (answered by MathLover1,greenestamps,MathTherapy)
Solve for x:
2^(3x-1) = 4^(2x)
I used logarithms to start this problem but I'm... (answered by josmiceli,MathTherapy)
How do you solve:
log2(3x+2)-log2(x)/log2(4)=3
3log2(x-1)+log2(4)=5
Logx(1/27)=3... (answered by stanbon)
log2(x)+log2(x+1)=log2(6) (answered by LinnW)
Log2 (x+1) - Log2 X= Log2... (answered by htmentor)
Log2 (x+1) - Log2 X= Log2 4
(answered by Gentle Phill)