SOLUTION: Hello, I worked this problem and only got half credit.
How can I work this as a systems of equations
y=x^2-4
x-y=-2
This is what I did
x=y-2
y=(y-2)^2-4
2y-4-4=0
Algebra.Com
Question 139463This question is from textbook College Algebra
: Hello, I worked this problem and only got half credit.
How can I work this as a systems of equations
y=x^2-4
x-y=-2
This is what I did
x=y-2
y=(y-2)^2-4
2y-4-4=0
This question is from textbook College Algebra
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given system
Solve for x in the second equation
Plug in
Foil
Subtract y from both sides
Combine like terms
Factor the right side
Now set each factor equal to zero:
or
or Now solve for y in each case
So our y-values are
or
Let's find x when
Start with the second equation
Plug in
Subtract
So when then
Let's find x when
Start with the second equation
Plug in
Subtract
So when then
-----------------------------------
Answer:
So the solutions are
(-2,0) or (3,5)
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