# SOLUTION: Find the solution of the exponential equation: 2^(2x+5) = 3^(x&#8722;48) in terms of logarithms. THANKS TO ANYONE WHO COULD HELP!!

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Find the solution of the exponential equation: 2^(2x+5) = 3^(x&#8722;48) in terms of logarithms. THANKS TO ANYONE WHO COULD HELP!!      Log On

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 Algebra: Exponent and logarithm as functions of power Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 139456: Find the solution of the exponential equation: 2^(2x+5) = 3^(x−48) in terms of logarithms. THANKS TO ANYONE WHO COULD HELP!!Answer by scott8148(6628)   (Show Source): You can put this solution on YOUR website!taking log __ (2x+5)log(2)=(x-48)log(3) distributing __ 2xlog(2)+5log(2)=xlog(3)-48log(3) subtracting xlog(3)+5log(2) __ 2xlog(2)-xlog(3)=-48log(3)-5log(2) factoring __ x[2log(2)-log(3)]=-48log(3)-5log(2) dividing by 2log(2)-log(3) __ x=[-48log(3)-5log(2)]/[2log(2)-log(3)]