SOLUTION: Please solve with steps 2(4^v+1) = 1

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Question 133277: Please solve with steps
2(4^v+1) = 1
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Please solve with steps
2(4^v+1) = 1
:
I assume you mean:
2%284%5E%28v%2B1%29%29 = 1
Divide both sides by 2 and you have;
4%5E%28v%2B1%29+=+1%2F2
Using logs:
log%284%5E%28v%2B1%29%29+=+log%281%2F2%29
log equivalent of exponents:
%28v%2B1%29%2Alog%284%29+=+log%281%2F2%29
Find the logs
.602(v+1) = -.301
:
Divide both sides by .602
v+%2B+1+=+-.301%2F.602
v + 1 = -.5
:
v = -.5 - 1
:
v = -1.5
:
Check solution on a calc: Enter 2(4^(-1.5+1)) = 1