# SOLUTION: Find the unknown in the equation log2 48 = log2(2^x+2 minus 2^x) Please show me the steps to get to the answer, which is x = 4 Stanbon,, you are the man

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Find the unknown in the equation log2 48 = log2(2^x+2 minus 2^x) Please show me the steps to get to the answer, which is x = 4 Stanbon,, you are the man      Log On

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 Question 133252: Find the unknown in the equation log2 48 = log2(2^x+2 minus 2^x) Please show me the steps to get to the answer, which is x = 4 Stanbon,, you are the manAnswer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!log2 48 = log2(2^(x+2) - 2^x) log2 48 = log2(2^2*2^x - 2^x) log2 48 = log2(2^x(4-1)) log2 48 = log2(3*2^x) log2 48 = log2 3 + log2 2^x log2 48 = log2 3 + x x = log2 48 - log2 3 x = log2 (48/3) x = log2 16 x = 4 =============== Cheers, Stan H.