SOLUTION: how can i solve logX + logX + 1 = log12 ?

Question 132012: how can i solve
logX + logX + 1 = log12 ?
Found 2 solutions by josmiceli, rapaljer:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

First get everything in terms of logs
1 = log(x)
If the base is , then I can write

, so

Now rewrite it

The general rule for logs is:
so,

If the logs are equal, the numbers are equal

answer
There is a negative square root also, but it makes
no sense here, since there is no log to the base 10
that will give me a negative number
check:

close enough

Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
logX + logX + 1 = log12
2logX+1=log12
1=log12-2logx
1=log12-logx^2

By basic definition of logarithms:

Since x must be a positive number,

R^2

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