# SOLUTION: Squareroot of 2x-5 + squareroot of 9+x=13 I square both sides and get 2x-5+9+x=169 and solve x=55 but it's wrong. What am I missing? Thanks for your help!

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: Squareroot of 2x-5 + squareroot of 9+x=13 I square both sides and get 2x-5+9+x=169 and solve x=55 but it's wrong. What am I missing? Thanks for your help!      Log On

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 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 129847: Squareroot of 2x-5 + squareroot of 9+x=13 I square both sides and get 2x-5+9+x=169 and solve x=55 but it's wrong. What am I missing? Thanks for your help!Answer by oscargut(891)   (Show Source): You can put this solution on YOUR website!(a+b)^2=a^2+2ab+b^2 so sqrt(2x-5)+sqrt(9+x)=13 2x-5+2sqrt(2x-5)sqrt(9+x)+9+x=169 3x+4+2sqrt(2x-5)sqrt(9+x)=169 3x-165 = -2sqrt(2x-5)sqrt(9+x) (3x-165)^2=4(2x-5)(9+x) if you need the rest please contact me