SOLUTION: Please help me solve the equation f(𝓍) = -log⅓ 3√𝓍 : → f(𝓍) = -log⅓ 3√𝓍 → f(𝓍) = - ⅓ log⅓ 𝓍 → f(𝓍) = ⅓ log3 𝓍

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve the equation f(𝓍) = -log⅓ 3√𝓍 : → f(𝓍) = -log⅓ 3√𝓍 → f(𝓍) = - ⅓ log⅓ 𝓍 → f(𝓍) = ⅓ log3 𝓍       Log On


   

Question 1207550: Please help me solve the equation f(𝓍) = -log⅓ 3√𝓍 :
→ f(𝓍) = -log⅓ 3√𝓍
→ f(𝓍) = - ⅓ log⅓ 𝓍
→ f(𝓍) = ⅓ log3 𝓍

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
We can't expect students to be familiar with the notation for this site.
Your problem should appear this way:

Please help me cross%28solve%29 highlight%28simplify%29 the equation f%28x%29=-log%281%2F3%2C%28root%283%2Cx%29%29%29 : 
→ f%28x%29=-log%281%2F3%2C%28root%283%2Cx%29%29%29 <--(Note: This is the same as what's given.
So it means this choice claims that the expression on the right cannot be
simplified.
→ f%28x%29=-expr%281%2F3%29log%281%2F3%2C%28x%29%29
→ f%28x%29=expr%281%2F3%29log%283%2C%28x%29%29

-------------------------------------------------------

f%28x%29=-log%281%2F3%2C%28root%283%2Cx%29%29%29

This tests you to see if you know that the cube root is the same as the
one-third power:

f%28x%29=-log%281%2F3%2C%28x%5E%281%2F3%29%29%29

This tests you to see if you know the rule of logs that the log of an
exponential is the exponent times the log of the base:

f%28x%29=-expr%281%2F3%29log%281%2F3%2C%28x%29%29

Which choice is that?

Edwin