SOLUTION: Log4x+log4(x-3)=1 find the solution

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Question 1207158: Log4x+log4(x-3)=1 find the solution
Found 2 solutions by Edwin McCravy, ikleyn:
Answer by Edwin McCravy(20056)   (Show Source): You can put this solution on YOUR website!
Sorry, I thought it was -
Answer by ikleyn(52795)   (Show Source): You can put this solution on YOUR website!
.
Log4x+log4(x-3)=1 find the solution
~~~~~~~~~~~~~~ 

Log4x + log4(x-3) = 1


    Assuming that the logarithms are base 4 . . . 


 +  = 1  

 = 1 
 
x*(x-3) = 4

 = 0

Factor left side

(x-4)*(x+1) = 0


Of two roots of the last equation, only x= 4 is the solution to the original equation.

x= -1 does not work, since only positive argument is allowed to logarithm.


ANSWER.  The original equation has a unique solution x= 4 in real numbers.

Solved.



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