SOLUTION: The population of J-Town in 2019 was estimated to be 76,500 people with an annual rate of increase of 2.4%. Part A. Write an equation to model future growth. Part B. What is the

Question 1206651: The population of J-Town in 2019 was estimated to be 76,500 people with an annual rate of increase of 2.4%.
Part A. Write an equation to model future growth.
Part B. What is the growth factor for J-Town?
Part C. Use the equation to estimate the population in 2072 to the nearest hundred people.

Found 2 solutions by ikleyn, MathLover1:
Answer by ikleyn(52794)   (Show Source): You can put this solution on YOUR website!
.
The population of J-Town in 2019 was estimated to be 76,500 people with an annual rate of increase of 2.4%.
Part A. Write an equation to model future growth.
Part B. What is the growth factor for J-Town?
Part C. Use the equation to estimate the population in 2072 to the nearest hundred people.
~~~~~~~~~~~~~~~~~~~

(A) P(t) = = , where t are years after 2019 (so 2020 is t= 1, 2021 is t=2 and so on . . . ) (B) the growth factor is 1.024. (C) P(2072) = = = 268,880.4 (approximately), and we say that the population will be about 268,900 to the nearest hundred people in 2072.

Solved.

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Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

Part A.
Write an equation to model future growth.

where (starting amount)
(rate, convert from % to decimal)

Part B. What is the growth factor for J-Town?
The is the growth factor of the function.

Part C. Use the equation to estimate the population in 2072 to the nearest hundred people.
from t0 is

...... round to whole number

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