SOLUTION: Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms into another atom (polonium-210 in this case) each da

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms into another atom (polonium-210 in this case) each da      Log On


   



Question 1196757: Bismuth-210 is an isotope that radioactively decays by about 13% each day, meaning 13% of the remaining Bismuth-210 transforms into another atom (polonium-210 in this case) each day. If you begin with 228 mg of Bismuth-210, how much remains after 7 days?
After 7 days,
mg of Bismouth-210 remains.

Answer by ikleyn(52786) About Me  (Show Source):
You can put this solution on YOUR website!
.

Since 13% of Bismuth-210 decay each day,  100%-13% = 87% remains.


After 7 days, the remaining amount of Bismuth-210 is

    228%2A0.87%5E7 = 86.014 mg.    ANSWER

Solved.

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On radioactive decay,  see the lesson
    - Radioactive decay problems
in this site.

You will find many similar  (and different)  solved problems there.


        Use this lesson as your handbook,  textbook,  guide,  tutorials, and  (free of charge)  home teacher.
        Learn the subject from there once and for all.


Also,  you have this free of charge online textbook in  ALGEBRA-I  in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Logarithms".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.