SOLUTION: A city is growing at the rate of 0.3% annually. If there were 2,520,000 residents in the city in 1993, find how many (to the nearest ten-thousand) are living in that city in 2000.

Question 1179745: A city is growing at the rate of 0.3% annually. If there were 2,520,000 residents in the city in 1993, find how many (to the nearest ten-thousand) are living in that city in 2000. Use Use y = 2,520.000(2.7)0.003t.

Answer by ikleyn(52818)   (Show Source): You can put this solution on YOUR website!
.

You just have a formula, and it is very good for you.

Substitute the value of t equal to   2000-1993 = 7 years into the formula
and calculate/compute the answer.

On the way, you may use your calculator or any appropriate software in your computer.

I wish you to have fun doing your job.

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If you want to see many other similar and different solved problems on population growth, see the lesson
    - Population growth problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Logarithms".

Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.

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