SOLUTION: find the co ordinate turning point on the curve y=2e^4x +8e^-4x and determined the nature of the turning point

Question 1171489: find the co ordinate turning point on the curve y=2e^4x +8e^-4x and determined the nature of the turning point
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
derivative is 8e^4x-32e^(-4x)
set that equal to 0
8e^4x=32 e^(-4x)
e^4x=4/e^(4x)
e^8x=4
8x=ln4
x=0.1733
when y=8
(0.1733, 8)
-
second derivative is 32e^4x-128e^(-4x); set that equal to 0
e^4x=4/e^4x and we get a positive result, so this is a minimum.

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