As soon as the last digit of n! is zero, it does not influence more on the last digit of the sum . . . So, the last requested digit comes from 1! + 2! + 3! + 4! + 5! = 1 + 2 + 6 + 24 + 120 and is, T H E R E F O R E, 3. ANSWER. The last digit of 1! + 2! + 3! + . . . + 2006! is.