SOLUTION: Pls help me. Given that logx^256=2 find log8^(1over x) Thanks

Question 1163251: Pls help me. Given that logx^256=2 find log8^(1over x) Thanks
Found 3 solutions by Theo, MathTherapy, ikleyn:
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
i understand this problem as:

given that log(x^256) = 2, find log(8^(1/x))

start with 2 = log(x^256)
this is true if and only if:
10^2 = x^256
take the 256th root of both sides of this equation to get:
(10^2)^(1/256) = (x^256)^(1/256)
solve this equation for x to get:
x = (10^2)^(1/256) = 1.018151722

you now want to find log(8^(1/x))
set y = that to get:
y = log(8^(1/x))
since x = 1.018151722, that becomes:
y = log(8^(1/1.018151722)
solve for y to get:
y = .8869895986

that should be your solution, if i understood the problem correctly.

Answer by MathTherapy(10556)   (Show Source): You can put this solution on YOUR website!

Pls help me. Given that logx^256=2 find log8^(~~1over~~ lower x) Thanks

If you meant: , then READ on! ------ Converting to EXPONENTIAL form ------ EXPONENTS are equal and so are the BASES Now, what's needed is: . If it's , then you're on your own, but should be able to figure it out, if you follow below! -------- Substituting 16 for x --- Letting the value of be "c." -------- Converting to EXPONENTIAL form 4c = 3 ------ BASES are equal and so are the EXPONENTS

Answer by ikleyn(52863)   (Show Source): You can put this solution on YOUR website!
.

Hello,

as I see, you systematically write your posts INCORRECTLY; so they are UNREADABLE.

If you want to present the formula/expression   ,

then write in your post   log base b (x).

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