SOLUTION: Pls help me. Given that log2^x+log3^81=1 find x?

Question 1163250: Pls help me. Given that log2^x+log3^81=1 find x?
Found 3 solutions by jim_thompson5910, MathTherapy, ikleyn:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Change of base property. Only change

Rewrite 81 as 3^4

Use the rule that log(x^y) = y*log(x).

Subtracting 4 from both sides

Convert from log form to exponent form

is the final answer. This is equivalent to 0.125 in decimal form.

Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
Pls help me. Given that log2^x+log3^81=1 find x?

Before we go any further, you need to know the value of , which we will name c. This gives us: ----- Converting to EXPONENTIAL form, based on the RULE: c = 4 ----- BASES are equal and so are the exponents Continuing, now becomes: ----- Converting to EXPONENTIAL form

Answer by ikleyn(52824)   (Show Source): You can put this solution on YOUR website!
.

Hello,

as I see, you systematically write your posts INCORRECTLY; so they are UNREADABLE.

If you want to present the formula/expression   ,

then write in your post   log base b (x).

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