You can put this solution on YOUR website!
log(96) = log(12*8)
log(96) = log(12)+log(8) ... use log rule log(x*y) = log(x)+log(y)
log(96) = 1.1+0.9 approximately
log(96) = 2.0 approximately
Using a calculator, the more accurate result is roughly log(96) = 1.98227123303957
The error comes from the fact we rounded these two values
log(8) = 0.90308998699194
log(12) = 1.07918124604762
to one decimal place
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