SOLUTION: A piece of charcoal is found to contain 39% of the element B that it originally had.
(a) When did the tree from which the charcoal came die? Use 5800 years as the half
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Question 1157061: A piece of charcoal is found to contain 39% of the element B that it originally had.
(a) When did the tree from which the charcoal came die? Use 5800 years as the half-life of the element B.
(b) Using a graphing utility, graph the relation between the percentage of the element B remaining and time.
(c) Using INTERSECT, determine the time that elapses until half of the the element B remains.
(d) Verify the answer found in part (a).
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A piece of charcoal is found to contain 39% of the element B that it originally had.
Use the radioactive decay formula: A = Ao*2^(-t/h), where
A = resulting amt after t time
Ao = initial amt
t = time of decay
h = half life of substance
:
(a) When did the tree from which the charcoal came die?
Use 5800 years as the half-life of the element B.
Assuming initial amt is 1
2^(-t/5800) = .39
ln(2) = ln(.39)
=
= -1.35845
t = -5800 * -1.3845
t = 7879 yrs
:
(b) Using a graphing utility, graph the relation between the percentage of the
element B remaining and time.
the equation for this: y = 100*2^(-x/5800)
:
(c) Using INTERSECT, determine the time that elapses until half of the the
element B remains. Did that
:
(d) Verify the answer found in part (a). confirmed, entered 7879 and got 39
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