SOLUTION: This is a composition of Functions problem If {{{f(x)=x^2-4}}} and{{{g(x)= sqrt(x+4)}}} find (f0g)(x) So I put f(g(x)) ={{{ f(sqrt(x+4))^2-4)}}} = now I a

Algebra ->  Algebra  -> Exponential-and-logarithmic-functions -> SOLUTION: This is a composition of Functions problem If {{{f(x)=x^2-4}}} and{{{g(x)= sqrt(x+4)}}} find (f0g)(x) So I put f(g(x)) ={{{ f(sqrt(x+4))^2-4)}}} = now I a      Log On

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Question 114640: This is a composition of Functions problem

If f%28x%29=x%5E2-4 andg%28x%29=+sqrt%28x%2B4%29 find (f0g)(x)
So I put f(g(x))
=+f%28sqrt%28x%2B4%29%29%5E2-4%29
= now I am stuck, do I add it all together or leave it like that??
Found 2 solutions by stanbon, edjones:
Answer by stanbon(48569) About Me  (Show Source):
You can put this solution on YOUR website!
If f%28x%29=x%5E2-4 andg%28x%29=+sqrt%28x%2B4%29 find (fog)(x)
----------------
fog(x) = f[g(x)] = f[sqrt(x+4)]
= [sqrt(x+4)]^2-4
= (x+4) - 4
= x
============================
Cheers,
Stan H.

Answer by edjones(7311) About Me  (Show Source):
You can put this solution on YOUR website!
You did the hard part.
=+f%28g%28x%29%29=%28sqrt%28x%2B4%29%29%5E2-4%29
=x+4-4
=x
Ed