SOLUTION: If g(x) = 4lnx + 1, what is the value of g^-1(ln 81 + 1)
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Question 1128775: If g(x) = 4lnx + 1, what is the value of g^-1(ln 81 + 1)
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!
g(x)=4lnx +1 g-1(ln 81+1)= ? If we let the unknown be y, we get this:
Using the definition of an inverse, we can rearrange the equation to make it look like this:
4lny+1=ln 81+1
4lny=ln 81
4lny=4ln 3
lny=ln 3
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