SOLUTION: 4^x^2-3x=1/16
Algebra.Com
Question 1122328: 4^x^2-3x=1/16
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Posted as "Exponential-and-logarithmic-function" type of problem, a guess is the equation was meant to be 4^(x^2-3x)=1/16. The parentheses are NEEDED.
Same base, both sides, so the exponents are also equal.
and YOU should be able to solve this.
RELATED QUESTIONS
3x/2 +... (answered by drk)
1 x+4
------ - ----
x^2-16... (answered by stanbon)
16^x=4^3x-2 (answered by edjones)
10(2x – 3) – 2(3x + 4) = 4(x – 1) +... (answered by jim_thompson5910)
3x^2-11x-4/x^2-16 divided by... (answered by jsmallt9)
-1/2 (X+4)... (answered by Alan3354)
(-3x^2+16)-(x^2+22x+4) (answered by Boreal)
4^(-3X+1)*16^(-X)=1^(-10) (answered by lwsshak3)
16^(x+4)=8^(3x-2) (answered by tommyt3rd)