SOLUTION: A coroner found that the temperature of a murdered body was
90 F at 11:00 pm and 88.5 F an hour later. The temperature of the room was
70 F. According to Newton’s law of Cooling,
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Question 1116731: A coroner found that the temperature of a murdered body was
90 F at 11:00 pm and 88.5 F an hour later. The temperature of the room was
70 F. According to Newton’s law of Cooling, the temperature, in F, of the body at time
t, in hours, is given by T(t)=70+ce^kt, where c and k are constants. Normal body temperature is 98.6 F. Find the values of c and k .
Determine when the murder was committed.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Body temperature at time zero is 90F, so
\ =\ 90\ =\ 70\ +\ ce^0)
So
Hence
Then
\ =\ 88.5\ =\ 70\ +\ 20e^k)
)
Then
t})
Solve for 
which will be a negative number of hours so that you can count back from 11:00 PM to approximate time of death.
John
My calculator said it, I believe it, that settles it
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