SOLUTION: In�1996,�an�outbreak�of�a�disease�infected�18people�in�a�large�community.��By�1997,�the number�of�those�infected�had�grown�to�38.��Find�an�exponential�growth�function�that�fits th

Question 1115870: In�1996,�an�outbreak�of�a�disease�infected�18people�in�a�large�community.��By�1997,�the number�of�those�infected�had�grown�to�38.��Find�an�exponential�growth�function�that�fits the�data.�(Round�decimals�to�three�places.)

Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
The initial population is 18 and 1 year(t=1) later it is 38
:
38 = 18 * e^(1*k), where k is the growth rate
:
e^(1*k) = 38/18
:
take the natural log(ln) of both sides of the =
:
k = ln(38/18) = 0.747
:
P(t) = 18 * e^(0.747*t), where P(t) is the population affected at time t(years since 1996)
:

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