SOLUTION: 5^x − 45(5^−x) + 4 = 0 Solve the equation. (Enter your answers as a comma-separated list. Round your answers to four decimal places.)

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Question 1111408: 5^x − 45(5^−x) + 4 = 0
Solve the equation. (Enter your answers as a comma-separated list. Round your answers to four decimal places.)

Answer by ikleyn(52799)   (Show Source): You can put this solution on YOUR website!
.
Answer. x = 1.

Solution

Introduce new variable u = .


Then your equation takes the form


u  - 45/u + 4 = 0,


u^2 + 4u - 45 = 0,


(u-5)*(u+9) = 0


The last equation has two roots u= 5 and u= -9,

but since u = ,  only positive "u" works.


Thus u = 5,   = 5  and x = 1.

Solved.

-------------
Introducing new variable is the STANDARD method of solving exponential equations.

See the lesson
    - Solving exponential equations
in this site.


Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lesson is the part of this online textbook under the topic "Exponential equations".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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