SOLUTION: log(base3)3/4 + log(base3)4/5 + log(base3)5/6 + log(base3)6/7 + log(base3)7/8 + log(base3)8/9 divided by log4/5 + log5/6 + log6/7 + log7/8 + log9/10 Please help me solve. Th

Question 1087381: log(base3)3/4 + log(base3)4/5 + log(base3)5/6 + log(base3)6/7 + log(base3)7/8 + log(base3)8/9 divided by log4/5 + log5/6 + log6/7 + log7/8 + log9/10
Please help me solve.
This is what I have so far, but I am not sure if I am on the right path.
log(base3) (3/4*4/5*5/6*6/7*7/8*8/9) divided by log (4/5*5/6*7/8*8/9*9/10)
Thank you!
Found 3 solutions by Fombitz, ikleyn, MathTherapy:
Answer by Fombitz(32388)   (Show Source): You can put this solution on YOUR website!
Yes, you're on the right track.
Do the multiplication,

So then the whole thing equals,

Answer by ikleyn(52799)   (Show Source): You can put this solution on YOUR website!
.

Next step notice that = = (after canceling the terms in the numerator and denominator) = (after canceling the terms in the numerator and denominator) Then = = -1 and = = = = , so your answer is . . . = = .

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

log(base3)3/4 + log(base3)4/5 + log(base3)5/6 + log(base3)6/7 + log(base3)7/8 + log(base3)8/9 divided by log4/5 + log5/6 + log6/7 + log7/8 + log9/10
Please help me solve.
This is what I have so far, but I am not sure if I am on the right path.
log(base3) (3/4*4/5*5/6*6/7*7/8*8/9) divided by log (4/5*5/6*7/8*8/9*9/10)
Thank you!

You first need to state whether the logs AFTER "divided by" are:
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