SOLUTION: How would you solve: 4^(x+1)=16^x

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Question 1080320: How would you solve:
4^(x+1)=16^x
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39630)   (Show Source): You can put this solution on YOUR website!
and .




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Answer by ikleyn(52894)   (Show Source): You can put this solution on YOUR website!
.
 =    is the same as    = .


Hence x+1 = 2x,  which implies   x = 1.


Check it on your own.

Solved.


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