SOLUTION: I get x=2 for this but I am not sure. Can someone help? Thank you. log4+log4(x-3)=1

SOLUTION: I get x=2 for this but I am not sure. Can someone help? Thank you. log4+log4(x-3)=1

Algebra.Com

Question 1079747: I get x=2 for this but I am not sure. Can someone help? Thank you.
log4+log4(x-3)=1

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Don't try to scam us.
Show how you got x=2.
----------
And, if the base of the logs is 4, specify that.

RELATED QUESTIONS
I have this exponential equation that I cannot seem to solve: 5^x = 4^x+1 I didn't... (answered by greenestamps,ikleyn)

I hope someone can clarify this. I'M CONFUSED!!! 2(log4 x + logx 4)=5 My working:... (answered by Alan3354)

I am having a hard time with this section. log4)x - log4)(x + 3) = -2 4e^(x+3) - 4 = 11 (answered by nerdybill)

Hello. I have the following polynomial to simplify using long division. {{{... (answered by stanbon,Alan3354)

what is the way to solve the logarithms a.) 2e^9x=4 b.)ln(4x − 3) = 4 and c.)... (answered by lwsshak3)

Solve the equation 4^(7x � 2) = 17^(x + 1). Round your answer to the nearest thousandth. (answered by Fombitz)

solve for x... (answered by nerdybill)

I have problems with logs please help log4 (x - 2) + log4 (x - 2) =... (answered by longjonsilver)

I'm trying to solve the following equation for x to three significant places, however,... (answered by Fombitz)