SOLUTION: (log3 (6))/3 + (log3 (11))/3 + (log3 (5))/3 I am supposed to condense, but we never talked about working with an expression "all over" another number. Is it the same as 1/3 (log

Algebra.Com
Question 1069444: (log3 (6))/3 + (log3 (11))/3 + (log3 (5))/3
I am supposed to condense, but we never talked about working with an expression "all over" another number. Is it the same as 1/3 (log3 6) + 1/3 (log3 11) + 1/3 (log3 5)?
When this assignment was introduced, we had not talked about changing log bases or anything like that, but is that involved?
Thank you!

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
(log3 (6))/3 + (log3 (11))/3 + (log3 (5))/3
I am supposed to condense, but we never talked about working with an expression "all over" another number. Is it the same as 1/3 (log3 6) + 1/3 (log3 11) + 1/3 (log3 5)?
log(6)/3 + log(11)/3 + log(5)/3 --- all base 3
= (log(6) + log(11) + log(5))/3
= log(6*11*5)/3
=
===================
When this assignment was introduced, we had not talked about changing log bases or anything like that, but is that involved?
---------
You can change the base or not.

RELATED QUESTIONS

Condense.... log3 (5x + 3) = 2 + log3... (answered by uma)
how do you condense the expression: log3 2x + 3 log3... (answered by Alan3354)
solve:... (answered by nerdybill)
solve log3(x-3) + log3(x+2) = log3... (answered by rothauserc)
Log3(x+1)-log3(x)+log3(3) (answered by Alan3354)
log3(x-6)=3 (answered by stanbon)
Rewrite the expression as a single logarithm. 3 log3 (4x + 3) + 6 log3 (2x -... (answered by Tatiana_Stebko,karaoz,Theo)
log3(x) +... (answered by stanbon)
log3 64-log3 8/3+ log3 2=log3... (answered by RAY100)