SOLUTION: {{{12^(x-2)=20}}} How do you find x? I did {{{ (x-2)log12=20}}} {{{ x-2= (20/log12)}}} {{{ x= (20/log12)+2}}} x=20.5326816

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Question 1069399:
How do you find x?
I did



x=20.5326816

Found 3 solutions by josgarithmetic, ikleyn, jorel1380:
Answer by josgarithmetic(39623)   (Show Source): You can put this solution on YOUR website!
Take logarithm of BOTH SIDES of the equation.
Answer by ikleyn(52832)   (Show Source): You can put this solution on YOUR website!
.
On logarithms, see the lessons
    - WHAT IS the logarithm
    - Properties of the logarithm
    - Change of Base Formula for logarithms
    - Solving logarithmic equations
    - Using logarithms to solve real world problems
in this site.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Logarithms".


Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
First off, you have to take the logarithm of both sides:
12^(x-2)=20
log 12^(x-2)=log 20
(x-2)log 12=log 20
x-2=log 20/log 12
x=(log 20/log 12)+2=3.20557135368 ☺☺☺☺

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