2a - 4b = 6 -------- eq (i)

- a + 2b = - 3 ------ eq (ii)

  a - 2b = 3 -------- Factoring out GCF, 2 in eq (i) ------ eq (iii)

       0 = 0 -------- Adding eqs (iii) & (ii)

The system has: INFINITELY many solutions 

Answer by ikleyn(52803)   (Show Source): You can put this solution on YOUR website!
 .

Your equations are EQUIVALENT, so actually it is ONE equation, not two.





Therefore, the "system" has INFINITELY many solutions.





These two equations represent ONE STRAIGHT line in a coordinate plane, and all points on this line are the "solutions".







For more details see the lesson



    - Geometric interpretation of a linear system of two equations in two unknowns 



in this site.







Also, you have this free of charge online textbook in ALGEBRA-I in this site



    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.





The referred lesson is the part of this online textbook under the topic 

"Systems of two linear equations in two unknowns".





 

RELATED QUESTIONS

solve by elimination 

a - 2b = -3 
-2a + 4b = 6  (answered by robertb)

2a-4b=6 and -a+2b=-3 solve using substituiton  (answered by erica65404)

3(a+4b)-2a(4a+2b) (answered by lynnlo)

2a+[3a-(2b-a)]+4b
 (answered by MichelleH8107)

(2a+b)/(a+4b)=3 if... (answered by richwmiller,ikleyn)

Please simplify... (answered by Nate,atif.muhammad)

Solve with elimination, explain each step given.

2a + 3b - 5c = -5 
-2a - 2b - c =... (answered by Fombitz,MathTherapy)

(5ab)(-2a^2b)^3 (answered by HyperBrain)

Given that {{{(3a+4b)/(2a-2b) =5, }}} find the value of... (answered by ikleyn)