SOLUTION: Exponential equation without logs. Solve for x: 5^(2x+4)= 125^(x-4)

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Question 106644: Exponential equation without logs. Solve for x:
5^(2x+4)= 125^(x-4)
Answer by stanbon(57290) About Me  (Show Source):
You can put this solution on YOUR website!
Exponential equation without logs. Solve for x:
5^(2x+4)= 125^(x-4)
5^(2x+4) = [5^3]^(x-4)
5^(2x+4) = 5^(3x-12)
Since the bases are the same the exponents are equal.
2x+4 = 3x-12
x = 16
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Cheers,
Stan H.