SOLUTION: 2^(2x+3) - 9*2^x +1 = 0

Algebra.Com
Question 1048666: 2^(2x+3) - 9*2^x +1 = 0
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
What is the 2nd exponent?
---
2^(2x+3) - 9*2^(x) +1 = 0
Or
2^(2x+3) - 9*2^(x+1) = 0

RELATED QUESTIONS

2^2x+3... (answered by jsmallt9)
1. (2x-3)(x+6) = (x-9)(x+2) 2. Solve and check (2x+3)(2x^2-5x-3) =... (answered by jim_thompson5910)
2x^3-x^2-18x+9=0 (answered by stanbon)
2x^3 +x^2-12x+9... (answered by Edwin McCravy)
1) 2(x-1)=5/2 2)... (answered by lynnlo)
(x-3)^2+(x+2)^2=17 (x-3)(x-3) + (x+2)(x+2)=17 (x^2-6x+9) + (x^2+4x+4) =17 x^2 - 6x... (answered by eperette)
3^2x - 3^x+1 +2 =... (answered by Aldorozos,robertb)
2x^2+x-9=0 (answered by edjones)
1. x^2 + 2x -15 = 0 2. 4x^2 + 32x +15 = 0 3. -2x^2 + x +1 = 0 4. 2x^2 +7x + 0 (answered by harpazo,Alan3354)