SOLUTION: 10log base 1o of m plus 2log base 10 of n minus log base 10 of p
or
10log_m+2log_n -log_⁡p the base is 10
I could not write in mathematical form
Thanks,
Algebra.Com
Question 1038775: 10log base 1o of m plus 2log base 10 of n minus log base 10 of p
or
10log_m+2log_n -log_p the base is 10
I could not write in mathematical form
Thanks,
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Notation: )
in plain text is log_b(x). Most folks assume base 10 if the base is omitted, so log(x) is generally interpreted as log_10(x). So your note that the logs are base 10 is appropriate because sometimes 
is used to mean 
which is 
. Also, get into the habit of putting the argument of the log in parentheses -- eliminates confusion.
So 10log_10(m) + 2log_10(n) - log_10 and (All logs base 10) 10log(m) + 2log(n) - log(p) would both have been interpreted as:
\ +\ 2\log_{10}(n)\ -\ \log_{10}(p))
Rules:
\ =\ \log_b(x^a))
The sum of the logs is the log of the product.
The difference of the logs is the log of the quotient.
So:
\ +\ 2\log_{10}(n)\ -\ \log_{10}(p)\ =\ \log_{10}\left(\frac{m^{10}n^2}{p}\right))
John
My calculator said it, I believe it, that settles it
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