SOLUTION: between the start of 2005 and the end of 2009, the number of Facebook users can be modelled by the exponent equation u=0.43*(3.17)^t, where u is the number of users in millions nd

Algebra.Com
Question 1035108: between the start of 2005 and the end of 2009, the number of Facebook users can be modelled by the exponent equation u=0.43*(3.17)^t, where u is the number of users in millions nd t is the number of years since 2004 (1<=t<6)
How do I find the year in which the exponential model predicts that the number of users would first reach 200 million? (I know that the 1 year since 2004, the number of Facebook users is 1.4 million)
Thanks for your help

Answer by jorel1380(3719)   (Show Source): You can put this solution on YOUR website!
If u is the number of Facebook users in millions, and u=.43*(3.17)^t, where t is the number of years since 2004, then:
200=.43*(3.17)^t
465.12=3.17^t
log 465.12=log 3.17^t
log 465.12=t log 3.17
t=log 465.12/log 3.17=5.32385131974 years after 2004 that the amount of Facebook users will reach 200 million. ☺☺☺☺

RELATED QUESTIONS

Between the start of 2005 and the end of 2009, the number of Facebook users can be... (answered by josmiceli)
Assessment Tool Data for the number of facebook users can be readily found on the... (answered by jim_thompson5910)
The total number of Ford drivers between 2011 and 2014 can be modelled by linear... (answered by solver91311)
The equation y=-1777x+27153 can be used to predict the number y of gun deaths in the... (answered by jorel1380)
According to data collected, 0.6% of Facebook users are under 13(the site is restricted... (answered by Boreal)
The equation y=-1777x 27,153 can be used to predict the number of y of gun deaths in the... (answered by stanbon)
The equation y=-1777x+27,153 can be used to predict the number y of gun deaths in the... (answered by rfer)
The total number of Ford drivers between 2011 and 2014 can be modelled by linear... (answered by advanced_Learner)
The equation y=112.18(1.134)^x gives the number of cellular phone users y​ (in... (answered by josmiceli)