SOLUTION: t(x)=log(base 2)(x+3)-1

Question 1034778: t(x)=log(base 2)(x+3)-1
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
t(x) = log2(x+3)-1
since log2 = log10/log2, you get:
t(x) = log(x+3)/log(2)-1.
let y = t(x), and you get:
y = log(x+3)/log(2)-1.
you h one equation with 2 variables, so the best you can do is solve for one of the variable in terms of the other, which we just did.
if you know the value of x, then you can solve for the value of y.
if you know the value of y, then you can solve for the value of x.
since you converted to base 10, you can use your calculator log function.
i don't know what else you can do with this equation.
for example:
when x = 100, you should get y = 5.686500527.
the graphing software i use gives me the same answer rounded to 3 decimal places.
the graph is shown below:
$$$

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