SOLUTION: What is the solution of: Log2X + Log2(X-12)=6
Algebra.Com
Question 1034578: What is the solution of: Log2X + Log2(X-12)=6
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Assume the problem is
adding logs is multiply so this is
the exponent equiv of logs
X(X-12) = 2^6
distribute X
X^2 - 12X = 64
Forms a quadratic equation
X^2 - 12X - 64 = 0
Factors to
(X-16)(X+4) = 0
X = 16; only the positive solution can be used in the original problem
:
;
See if this checks out wit X=16
16 is the 4th & 4 is the 2nd power of 2, therefore
4 + 2 = 6
RELATED QUESTIONS
log2x+log2(x-6)=4 (answered by longjonsilver)
Log2x+log2(x+2)=log2(x+6) (answered by drk,CharlesG2)
What is the solution of log2x + 6 8 = 3?
The 2x+6 part is beneath the log part.
(answered by richard1234)
Below is the graph of
y=log2x
.
Translate it to become the graph of... (answered by Theo)
5 log2 (2 x – 3) = log2 (2 x – 3) + 12, what is the value of... (answered by lwsshak3)
log2(x+3)+log2x=2 (answered by Alan3354)
find the value of x
log2x+log2(x-3)=2
thanks for the help
Lee... (answered by Cintchr)
the range of f(x)=log2x is... (answered by venugopalramana)
log2(x-1)+ log2 (x-4)=log2(2x-6)?what is the answer?
(answered by jsmallt9)