SOLUTION: If log(base 3)5=1.465 and log(base 3) 2=0.6309, what is the aproximate value of log(base 3)30?

Question 1004990: If log(base 3)5=1.465 and log(base 3) 2=0.6309, what is the aproximate value of log(base 3)30?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
If log(base 3)5=1.465 and log(base 3) 2=0.6309, what is the aproximate value of log(base 3)30?
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log3(30) = log3[2*3*5) = log3(2)+log3(3)+log3(5) = 0.6309+1+1.465 = 3.0959
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Cheers,
Stan H.

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