SOLUTION: A rectangle has an area of X^3 � 6X^2 + 15X � 28 square feet. Its width is X � 4 feet.

Question 100121: A rectangle has an area of X^3 � 6X^2 + 15X � 28 square feet. Its width is X � 4 feet.

Answer by AlgebraII(1) (Show Source): You can put this solution on YOUR website!
Your first step is to look at the equation for the area of a rectangle which is
Area=length times width
So your problem would look like this...
x^3-6^2+15x-24= x-4 times l (l=to length)
you want to end up with just l on one side, so you get rid of the x by subracting from both sides, which would look like this...
x^3-6^2+14x-24 notice that 15 x changed to 14 x because you subtracted an x.
now to get rid of the 4 you divide on both sides, and it will look like this...
x^3/4-6x^2/4+14x/4-24/4 if you simplify you�d end up with
x^3/4-3x^2/2+7x/2+6 and that would be your answer.

RELATED QUESTIONS
A rectangle has an area of X^3 � 6X^2 + 15X � 28 square feet. Its width is X � 4 feet. (answered by edjones)

A rectangle has a area of X^3-6X^2+15X-28 square feet. Its width is X-4 feet. What is its (answered by edjones)

if the length of a rectangle is 3 feet greater than the width and it has an area of 28... (answered by JBarnum)

A rectangular deck has an area of (x2 + 6x + 8) square feet. If its width is (x + 2) feet (answered by vleith,rapaljer)

the area of the rectangle is x^3 -2x^2 -5x+6 square feet. If its length is x-3 feet, what (answered by LinnW)

A rectangle with a width of (-5x + 4) feet and a length of (-6x +7) feet, has an area of (answered by stanbon)

a rectangle has an area of 20 square feet and a length of 6 feet.what is its width (answered by ikleyn)

A rectangle has an area of 2045.44 square feet and a perimeter of 184 feet. Find its... (answered by josgarithmetic)

A rectangle has a length of x. It's width is 3 feet longer than twice the length. Find... (answered by swincher4391)