# SOLUTION: I have to solve N(t) =N_0(2)^t/d for t using logarithms. This is what I have and I'd really appreicate some help on it. logN(t) = log(N_0(2)^t/d) logN(t) = t/d log(N_0)(2) t/d

Algebra ->  -> SOLUTION: I have to solve N(t) =N_0(2)^t/d for t using logarithms. This is what I have and I'd really appreicate some help on it. logN(t) = log(N_0(2)^t/d) logN(t) = t/d log(N_0)(2) t/d       Log On

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 Click here to see ALL problems on Exponential-and-logarithmic-functions Question 29022: I have to solve N(t) =N_0(2)^t/d for t using logarithms. This is what I have and I'd really appreicate some help on it. logN(t) = log(N_0(2)^t/d) logN(t) = t/d log(N_0)(2) t/d = log(N_0(2)) / log(N(t) t = log(N_0(2)) / log(N(t) * d Is this right? Thank you.Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!SEE BELOW I have to solve N(t) =N_0(2)^t/d for t using logarithms....WHAT IS THIS N_0(2) SYMBOL?..ANY WAY I AM IGNORING IT!BETTER PUT BRACKETS TO (T/D)AS OTHERWISE IT MAY MEAN ONLY^T AND MULTIPLY THE ANSWER WITH D.... This is what I have and I'd really appreicate some help on it. logN(t) = log(N_0(2)^t/d)....OK logN(t) = t/d log(N_0)(2)......OK t/d =LOG(N(T))/ log(N_0(2))....NO..IT IS OTHERWAY ROUND...IT IS t =D*{LOG(N(T))/ log(N_0(2))}. IS THE CORRECT ANSWER...BUT CHECK IF N_0(2) HAS ANY MEANING.