# SOLUTION: can you help me factor 4x^3+4x^2y-24xy^2

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 Question 236035: can you help me factor 4x^3+4x^2y-24xy^2Answer by Theo(3556)   (Show Source): You can put this solution on YOUR website!4x^3+4x^2y-24xy^2 factor out 4x to get: 4x * (x^2 + xy - 6y^2) if you didn't have the y there, your equation within the parentheses would have been: x^2 + x - 6 which factors as (x+3) * x-2) if you add a y into the right side of each of the factors, you get: x^2 + xy - 6y^2 = (x+3y) * (x-2y) this looks like it will actually work. your factors should be: 4x * (x+3y) * (x-2y) to confirm they are good, work back to see if you can get the original equation again. (x + 3y) * (x-2y) becomes: x^2 - 2xy + 3xy - 6y^2 which becomes x^2 + xy - 6y^2 multiply that by 4x to get: 4x * (x^2 + xy - 6y^2) becomes: 4x^3 + 4x^2y - 24xy^2 your original equation is: 4x^3 + 4x^2y - 24xy^2 since they're the same, your answer is confirmed. your answer is: 4x * (x+3y) * (x-2y)