SOLUTION: The expression 2(l+ w) may be used to find the perimeter of a rectangle. What are the length and width of a rectangle if the area is 13 1/2 square units and the length of one side
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Question 94377This question is from textbook Algebra 1
: The expression 2(l+ w) may be used to find the perimeter of a rectangle. What are the length and width of a rectangle if the area is 13 1/2 square units and the length of one side is 1/5 the measure of the perimeter?
This question is from textbook Algebra 1
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The expression 2(l+ w) may be used to find the perimeter of a rectangle. What are the length and width of a rectangle if the area is 13 1/2 square units and the length of one side is 1/5 the measure of the perimeter?
:
Using decimal for 1/5. L = .2 * perimeter:
L = .2(2(L+W))
L = .4(L+W)
L = .4L + .4W
1L - .4L = .4W
.6L = .4W
:
Area is given as 13.5 sq units
L * W = 13.5
W = 13.5/L
:
Substitute (13.5/L) for W in the .6L = .4W equation
.6L = .4
.6L =
Multiply equation by L
= 5.4
:
Divide both sides by .6
=
:
= 9
L =
L = 3
:
Find W:
W = 13.5/3
W = 4.5 units
:
Perimeter = 2(3) + 2(4.5) = 15
Length/Perimeter: 3/15 = 1/5
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