SOLUTION: Find two consecutive integers whose product is 8 less than the square of the smaller number. (Enter your answers as a comma-separated list.)

Algebra.Com
Question 897678: Find two consecutive integers whose product is 8 less than the square of the smaller number. (Enter your answers as a comma-separated list.)
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!






The integers are -8 and -7.

Recheck in equation:
(-8)(-7)=-8+(-8)^2
56=-8+64
56=64-8=56 yes.

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