SOLUTION: 7-(-y-5)= 2(y+3)-6(y+1) want to know if I should distributive only the neg. sign to the -y or the 7 at the beginning of the problem, I came up with 5 over 11y but text book s

Question 89024: 7-(-y-5)= 2(y+3)-6(y+1)

want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5
Found 2 solutions by malakumar_kos@yahoo.com, praseenakos@yahoo.com:
Answer by malakumar_kos@yahoo.com(315) (Show Source): You can put this solution on YOUR website!

7-(-y-5)= 2(y+3)-6(y+1)
want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5
The - sign should be distributive only to -y &-5 and not 7

The solution goes like this : 7-(-y-5) = 2(y+3)-6(y+1)
7+y+5 = 2y+6-6y-6
y+12 = -4y+0
y+4y = -12
5y = -12 or y = -12/5

Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
Question:

7-(-y-5)= 2(y+3)-6(y+1)

want to know if I should distributive only the neg. sign to the -y or the 7
at the beginning of the problem, I came up with 5 over 11y
but text book states -12 over 5

Answer:
7-(-y-5)= 2(y+3)-6(y+1)

For solving this you have to remove the parenthesis first.
Here negative sign is distributive only to -y and -5

Hope you are familiar with multiplication of signs...

here -(-y) = +y
-(-5) = +5
2(y) = 2y
2(3) = 6
-6(y) = -6y
-6(1) = -6

so 7-(-y-5)= 2(y+3)-6(y+1)
==> 7 + y + 5 = 2y + 6 - 6y - 6

==> 7 + 5 + y = 2y - 6y + 6 - 6

==> 12 + y = -4y

Add 4y on both sides.....

==> 12 + y + 4y = -4y + 4y

==> 12 + 5y = 0

Subtract 12 from both sides....

==> 12 + 5y - 12 = 0 - 12

==> 5y = -12

Divide both sides by 5

==> 5y/5 = -12/5

==>

Hope you found the explanation useful.

Regards.

Praseena.

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