SOLUTION: Factor and solve:
2x^5+4x^4-4x^3-8x^2=0
Algebra.Com
Question 866084: Factor and solve:
2x^5+4x^4-4x^3-8x^2=0
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
2x^2 *(x^3+2x^2-2x-4) = 0
2x^2 *(x+2)* (x^2-2) = 0
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