SOLUTION: [2x^2 - 5x + 3]/ [3x^2 - 7x +4] divided by [2x^2 + x - 6]/ [3x^2 + 2x - 8] The answer I got is x +1 / x - 1

Algebra ->  Algebra  -> Distributive-associative-commutative-properties -> SOLUTION: [2x^2 - 5x + 3]/ [3x^2 - 7x +4] divided by [2x^2 + x - 6]/ [3x^2 + 2x - 8] The answer I got is x +1 / x - 1       Log On

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Question 76467: [2x^2 - 5x + 3]/ [3x^2 - 7x +4] divided by [2x^2 + x - 6]/ [3x^2 + 2x - 8]
The answer I got is x +1 / x - 1

Answer by Cintchr(475) About Me  (Show Source):
You can put this solution on YOUR website!
+%28%282x%5E2+-+5x+%2B+3%29%2F%283x%5E2+-+7x+%2B4%29%29%2F%28%282x%5E2+%2B+x+-+6%29%2F%283x%5E2+%2B+2x+-+8%29%29+
There is a rule that states ....
+%28a%2Fb%29%2F%28c%2Fd%29+=+%28ad%29%2F%28bc%29+
Apply this to your problem
+%28%282x%5E2-5x%2B3%29%283x%5E2%2B2x-8%29%29%2F%28%283x%5E2-7x%2B4%29%282x%5E2%2Bx-6%29%29+
Factor all parts
+%28%282x-3%29%28x-1%29%283x-4%29%28x%2B2%29%29%2F%28%283x-4%29%28x-1%29%282x-3%29%28x%2B2%29%29+
Cancel the 2x-3
+%281%28x-1%29%283x-4%29%28x%2B2%29%29%2F%28%283x-4%29%28x-1%291%28x%2B2%29%29+
Cancel the x-1
+%281%2A1%283x-4%29%28x%2B2%29%29%2F%28%283x-4%291%2A1%28x%2B2%29%29+
Cancel the 3x-4
+%281%2A1%2A1%28x%2B2%29%29%2F%281%2A1%2A1%28x%2B2%29%29+
Cancel the x+2
+%281%2A1%2A1%2A1%29%2F%281%2A1%2A1%2A1%29+
Reduce
+1+