You can
put this solution on YOUR website!Check to make sure that you copied the problem correctly. If the problem is correct as
you posted it, the answer is
.
If you posted the problem correctly, then I suspect that you are adding not subtracting
during the division process.
.
For example. You got the first division correct ... and the first quotient term is, as you
found,
. When you multiply this back times the divisor
the product is:
.
.
when you subtract this from
you CHANGE THE SIGNS of
to
get
and then you add this to
. The result is:
.
.
.
You then bring down the -5x term. So the next division is
into
.
This division will result in +15x and multiplying it back the
times
results in
. Subtract this from
. Do that by changing the
signs to
and adding it to
to get
.
.
Divide the
by
to get 40. Back multiply this to get
equals
. Subtract this from
by changing the signs to
.
and adding that to
to get
. The 121 is the remainder
and it can be divided by the divisor
. This will make the answer to this division
problem:
.
.
with a remainder of
.
Hope this helps you to understand the process of algebraic long division.
.
(