SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2

SOLUTION: how do you factor these trinomials? 90x^2 - 143x + 56 and 132x^2 - 199x + 60 PLEASE help me!!!

Question 76358: how do you factor these trinomials?
90x^2 - 143x + 56 and 132x^2 - 199x + 60
PLEASE help me!!!
Answer by scott8148(6628) (Show Source): You can put this solution on YOUR website!
see problem 76029 for details of a factoring technique

first equation...90*56=5040...factors to get -143 are -80 and -63...factors of 90 are 9 and 10...factors of 56 are -8 and -7

so 90x^2 - 143x + 56 = (10x - 7)(9x - 8)

second equation...132*60=7920...factors to get -199 are -144 and -55...factors of 132 are 11 and 12...factors of 60 are -5 and -12

so 132x^2 - 199x + 60 = (12x - 5)(11x - 12)
RELATED QUESTIONS
Factor each of the following trinomials completely. x^2-11x-60 Help me please.... (answered by Earlsdon)

How do you factor trinomials that are equal to something such as:x^2-x+56=17x (answered by Earlsdon)

Can you please show me how to factor these two trinomials? 4x^2 + 16x - 8 x^2 -... (answered by MathLover1)

Factor as completely as possible. a) {{{x^3-4x}}} b) {{{xy-x+8y-8}}} c)... (answered by Mathematicians,JBarnum)

Please help me factor the trinomials. {{{25x^2 -15x + 2}}} (answered by macston)

How do you factor trinomials? like... (answered by venugopalramana)

How do you factor 5xy^2-9xy+4x? factoring... (answered by josmiceli)

Factor each of the following trinomials completely: x^2-11x-60 Please help me with... (answered by checkley75)

How do you factor completely... (answered by richwmiller)